1/x=(x-34)/(2x)^2

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Solution for 1/x=(x-34)/(2x)^2 equation: 


D( x )

(2*x)^2 = 0

x = 0

(2*x)^2 = 0

(2*x)^2 = 0

4*x^2 = 0 // : 4

x^2 = 0

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

1/x = (x-34)/((2*x)^2) // - (x-34)/((2*x)^2)

1/x-((x-34)/((2*x)^2)) = 0

(-1*(x-34))/(4*x^2)+1/x = 0

(-1*x*(x-34))/(4*x*x^2)+(1*4*x^2)/(4*x*x^2) = 0

1*4*x^2-1*x*(x-34) = 0

3*x^2+34*x = 0

3*x^2+34*x = 0

x*(3*x+34) = 0

3*x+34 = 0 // - 34

3*x = -34 // : 3

x = -34/3

x*(x+34/3) = 0

(x*(x+34/3))/(4*x*x^2) = 0

(x*(x+34/3))/(4*x*x^2) = 0 // * 4*x*x^2

x*(x+34/3) = 0

( x+34/3 )

x+34/3 = 0 // - 34/3

x = -34/3

( x )

x = 0

x in { 0} 

x = -34/3

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